5x^2-44x+9=0

Solution for 5x^2-44x+9=0 equation:

5x^2-44x+9=0

a = 5; b = -44; c = +9;
Δ = b2-4ac
Δ = -442-4·5·9
Δ = 1756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1756}=\sqrt{4*439}=\sqrt{4}*\sqrt{439}=2\sqrt{439}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-2\sqrt{439}}{2*5}=\frac{44-2\sqrt{439}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+2\sqrt{439}}{2*5}=\frac{44+2\sqrt{439}}{10}
$